The following program is my ACcepted code for UVA-10370 .
It's a for everybody to learn and discuss.
If there is any mistake or comment, please let me know. :D
此乃UVA 10370 的AC code!
Please feel free to use it after adding this blog as an reference. (http://autekroy.blogspot.tw) If there is any mistake or comment, please let me know. :D
歡迎使用與分享任何內容,但請記得標示此部落格為出處。(http://autekroy.blogspot.tw/) 如果有發現任何的錯誤與建議請留言或跟我連絡。 : )
It's a for everybody to learn and discuss.
If there is any mistake or comment, please let me know. :D
此乃UVA 10370 的AC code!
歡迎一同討論學習,如有錯誤與任何建議請留言 : )
點這裡看題目 Click here to see this Problem!
//This program is for UVA 10370 Above Average
//題目來源 Problem link: http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=15&page=show_problem&problem=1311
#include<stdio.h>
#include<stdlib.h>
using namespace std;
int main()
{
int c, n, score[1001], count = 0;
double sum, aver;
scanf("%d", &c);
while(c--)
{
scanf("%d", &n);
sum = 0.0;
aver = 0.0;
count = 0;
for(int i = 0; i < n; i++)
{
scanf("%d", &score[i]);
sum += score[i];
}
aver = sum / (double)n;
for(int i = 0; i < n; i++)
if(score[i] > aver)
count ++;
printf("%.3lf%%\n", (double)count / (double)n * 100.0);
}
return 0;
}
Please feel free to use it after adding this blog as an reference. (http://autekroy.blogspot.tw) If there is any mistake or comment, please let me know. :D
歡迎使用與分享任何內容,但請記得標示此部落格為出處。(http://autekroy.blogspot.tw/) 如果有發現任何的錯誤與建議請留言或跟我連絡。 : )
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