UVa OJ - 10071 Back to High School Physics

The following program is my ACcepted code for UVA-10038 .
It's a for everybody to learn and discuss.
If there is any mistake or comment, please let me know.  :D

此乃UVA 10038 的AC code!

歡迎一同討論學習，如有錯誤與任何建議請留言 : )

點這裡看題目 Click here to see this Problem!

一個簡單的高中物理題
讓我們回想一下這個方程式: V = V0 + a * t
我把 2 倍時間的速度稱為 "V2"
此V2 =  V0 + 2 * a * t
而經過 2 倍時間的位移 = (V2 + V0) * 2 * t / 2
= (2 * V0 + 2 * a * t ) * t = 2 * (V0 + a * t) * t = 2 * V * t !

It's a simple High School Physics.
Let's remind this equation: V = V0 + a * t .
I call the V in twice of that time "V2".
This V2 = V0 + 2 * a * t .
and the displacement be in twice of that time = (V2 + V0) * 2 * t / 2
= (2 * V0 + 2 * a * t ) * t = 2 * (V0 + a * t) * t = 2 * V * t !

//This program is for UVA 10071 Back to High School Physics
//題目來源 Problem link: http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=12&page=show_problem&problem=1012

#include<stdio.h>
#include<stdlib.h>

int main()
{
    int t, v;
 
    while(scanf("%d %d", &v, &t) != EOF)
    {
        //the displacement can be negative!
        printf("%d\n", 2 * t * v);
    }
    return 0;
}

Please feel free to use it after adding this blog as an reference. (http://autekroy.blogspot.tw) If there is any mistake or comment, please let me know. :D 

歡迎使用與分享任何內容，但請記得標示此部落格為出處。(http://autekroy.blogspot.tw/) 如果有發現任何的錯誤與建議請留言或跟我連絡。 : )